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October 19th, 2002, 08:54 PM
#31
Inactive Member
To Wiseman's Q - No it doesnt. I have no idea what the answer is, but its 50/50 chance. ^^
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October 20th, 2002, 04:40 AM
#32
Inactive Member
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October 20th, 2002, 10:39 AM
#33
HB Forum Owner
The answer to my sets question is:
A set cannot be a member of itself. (Bertrand Russell 1902)
[img]tongue.gif[/img]
<font color="#a62a2a" size="1">[ October 20, 2002 07:39 AM: Message edited by: -Wiseman- ]</font>
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October 20th, 2002, 11:48 AM
#34
Inactive Member
SDamn, my guess failed ><
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October 20th, 2002, 03:40 PM
#35
Inactive Member
im only gonna hurt myself if i try to find the answer =/
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October 20th, 2002, 05:42 PM
#36
Inactive Member
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October 20th, 2002, 08:40 PM
#37
HB Forum Owner
Well, actually, no such "set of sets that do not contain themselves" is possible.
Let's divide all kinds of sets into:
- Classes of individuals
- Classes of classes of individuals
- Classes of classes of classes of individuals
and so on.
A class cannot be an individual; a class of classes of individuals cannot be a class of individuals, and so on.
It's a bit messy, but basically, this disallows my "set of sets that do not contain themselves".
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October 20th, 2002, 09:57 PM
#38
Inactive Member
I see. I totally understood that. ^^uu
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October 20th, 2002, 11:07 PM
#39
Inactive Member
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October 20th, 2002, 11:15 PM
#40
Inactive Member
damn, I was gonna answer that!
:-P
I woulda been on the right track I think (I was gonna answer no) but I see better now. :-)
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